its like sum up entries of each user in order table backwards (i.e from last entry to the first) and find the entry that has sum > $500.
If there is some user who didnt even make 500 till now in my shop return the first date of transaction/order.ex:
Orders(order_id, user_id, amount_paid, create_timestamp)
values:
(1, 1, 100, 1)
(2, 1, 300, 2)
(3, 2, 100, 2)
(4, 2, 100, 3)
(5, 1, 100, 4)
(6, 1, 200, 5)
(7, 2, 150, 5)for user 1: the order_id = 2
for user 2: the order_id = 3 (coz he couldnt make 500)
On Thu, Nov 6, 2008 at 10:40 PM, Harold A. Giménez Ch.
<harold.gimenez@gmail.com> wrote:
I personally would help if I understood what you need. I'm sure others feel the same way. Provide DDL, sample data, and expected result of the query. Maybe you'll have better luck... On Thu, Nov 6, 2008 at 11:15 AM, Devil™ Dhuvader
<gibsosmat@gmail.com> wrote:
none can help me?
On Tue, Nov 4, 2008 at 9:08 PM, Devil™ Dhuvader
<gibsosmat@gmail.com> wrote:
hi,
I need some help in creating a sql.
the problem is as below.
assume that:
I am a store keeper
and I have the list of customer(user_id) transactions in my order table.
schema: Orders(order_id, user_id, amount_paid, create_timestamp)
I want to give discount of 10% for the customer who made orders of worth (sum) at least $500 in the least time from now (i.e last few days, but NOT ALL TIME LEAST TIME TO BUY $500 WORTH GOODS).
and 9% discount for the customer who made $500 in second least time from now.
and so on
there is no time constraint.
it customer could take any amount of time to make $500.
the customer might not even made $500 bill till now in that case I should get the first date.
the result can take upto the first entry time of the table itself.
in short its like sum up entries of each user in order table backwards (i.e from last entry to the first) and find the entry that has sum > $500.
If there is some user who didnt even make 500 till now in my shop return the first date of transaction/order.
can anyone help me on this?