plpgsql function and constraints

Поиск
Список
Период
Сортировка
Искать
От
Jakub Ouhrabka
Тема
plpgsql function and constraints
Дата
Msg-id
Pine.LNX.4.33.0108302037470.9002-100000@u-pl0
Ответ на
bug in hash indexes??? (Jakub Ouhrabka)
Список
Дерево обсуждения
Re: replication? Justin Clift <justin@postgresql.org>
hi,

i have table1 and table2. in table1 there is a foreign key referencing id
in table2. i'd like to do something like this:

CREATE FUNCTION foo() RETURNS INTEGER AS '
DECLARE
BEGIN
    UPDATE table1 SET not_key = 100;
    DELETE FROM table1;
    DELETE FROM table2;
    RETURN 0;
END;
' LANGUAGE 'plpgsql';

when i run select foo(); i always get:

ERROR:   referential integrity violation - key referenced from
table1 not found in table2

(i think that's because constraints are checked at the end of statement
and this function is treated as one statement... or am i wrong?)

when i try it in psql as separate commands in one transaction it's ok:
BEGIN;
UPDATE table1 SET not_key = 100;
DELETE FROM table1;
DELETE FROM table2;
COMMIT;

is there any way to do something like this in plpgsql function?

thanks in advance,

kuba

В списке pgsql-general по дате отправления
От: Albert Reiner
Дата:
От: David M. Richter
Дата:
Сообщение: Compaq iPaQ - Postgresql
FAQ