Re: NOTICE: CREATE TABLE will create implicit trigger(s) for FOREIGN KEY check(s) ?

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От Joel Burton
Тема Re: NOTICE: CREATE TABLE will create implicit trigger(s) for FOREIGN KEY check(s) ?
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Msg-id Pine.LNX.4.21.0104261348040.29630-100000@olympus.scw.org
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Ответ на NOTICE: CREATE TABLE will create implicit trigger(s) for FOREIGN KEY check(s) ?  ("Christian Marschalek" <cm@chello.at>)
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On Thu, 26 Apr 2001, Christian Marschalek wrote:

> Can anyone tell me what this notice means?
>
> NOTICE:  CREATE TABLE will create implicit trigger(s) for FOREIGN KEY
> check(s) ?

You probably did something like this:

CREATE TABLE child (
  id REFERENCES parent ... )

and PostgreSQL handles this sort of foreign key referential
integrity by using a special kind of trigger.

This notice just lets you know this is happening.



--
Joel Burton   <jburton@scw.org>
Director of Information Systems, Support Center of Washington


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