Re: [SQL] select a part of a name

On Wed, 8 Dec 1999, Moray McConnachie wrote:
> 
> > use: where name like '%names%'
> 
> Except that the user specified he wanted to be able to find Tom Jones
> and jonas from the search text jon, so you either need to use:
> 
> where lower(name) like ('%' ŚŚ lower(searchtext) ŚŚ '%')

> or something similar, which is slow unless you have an index on
> lower(name), and even then.
I think, this case always will be slow. Because the first '%'. I'm not
sure about all of access methods, and comparsion operators. But this
combination of them (btree/hash -- like) can't do indexed substr lookup.
Is there any tricks, to do it?

--nek;(