Re: Left Outer Join Question

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От
Christopher Kings-Lynne
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Re: Left Outer Join Question
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GNELIHDDFBOCMGBFGEFOGEJCCBAA.chriskl@familyhealth.com.au
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Re: Left Outer Join Question "Andy Marden" <amarden@usa.net>
> "Christopher Kings-Lynne"  writes:
> > What's probably happening is that count isn't counting NULLs?
> 
> As per spec.  If you want to count records independently of whether
> any particular column is NULL or not, use count(*).  See the docs,
> notably
> http://www.ca.postgresql.org/users-lounge/docs/7.2/postgres/sql-ex
> pressions.html#SYNTAX-AGGREGATES

OK, Edward - I guess Tom means do this?:

select category.name, count(items.*) from category left outer join
items on (category.recordnum = items.catnum) where category.recordnum =
section_subcats.catnum and section_subcats.sectionnum = 1 and
items.clientnum = 333 group by category.name;

Chris


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От: Edward Murray
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Сообщение: Re: Left Outer Join Question
От: Edward Murray
Дата:
Сообщение: Re: Left Outer Join Question
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