Re: Left Outer Join Question
| От | Christopher Kings-Lynne |
|---|---|
| Тема | Re: Left Outer Join Question |
| Дата | |
| Msg-id | GNELIHDDFBOCMGBFGEFOGEJCCBAA.chriskl@familyhealth.com.au обсуждение исходный текст |
| Ответ на | Re: Left Outer Join Question (Tom Lane <tgl@sss.pgh.pa.us>) |
| Список | pgsql-sql |
> "Christopher Kings-Lynne" <chriskl@familyhealth.com.au> writes: > > What's probably happening is that count isn't counting NULLs? > > As per spec. If you want to count records independently of whether > any particular column is NULL or not, use count(*). See the docs, > notably > http://www.ca.postgresql.org/users-lounge/docs/7.2/postgres/sql-ex > pressions.html#SYNTAX-AGGREGATES OK, Edward - I guess Tom means do this?: select category.name, count(items.*) from category left outer join items on (category.recordnum = items.catnum) where category.recordnum = section_subcats.catnum and section_subcats.sectionnum = 1 and items.clientnum = 333 group by category.name; Chris
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