Re: escape character in a function
От | Henshall, Stuart - WCP |
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Тема | Re: escape character in a function |
Дата | |
Msg-id | E2870D8CE1CCD311BAF50008C71EDE8E01F7485F@MAIL_EXCHANGE обсуждение исходный текст |
Ответ на | escape character in a function ("Patrick Hatcher" <PHatcher@macys.com>) |
Ответы |
pg_setlocale()
|
Список | pgsql-novice |
Try doubleing the apostraphe again, ie: set div_name = ''RICH''''S'' Cheers, - Stuart > -----Original Message----- > From: Patrick Hatcher [mailto:PHatcher@macys.com] > Sent: 23 April 2002 22:26 > To: pgsql-novice@postgresql.org > Subject: [NOVICE] escape character in a function > > > Howdy > How do I do an escape character in a function to for a word > that has an > apostrophe like: RICH'S. I tried ''RICH\'S'', but when I run > my function, > I get back mismatch parentheses. > TIA > > REATE FUNCTION "sp_updaterlg"() RETURNS "int4" AS ' > begin > update bcp_cust > set div_name = ''RICH\'S'' > where > div_store is not null > and instr(div_store,''RICH\'S'',1) >0; > > return 1; > end; > ' LANGUAGE 'plpgsql'; > > Patrick Hatcher > Macys.Com > > > > ---------------------------(end of > broadcast)--------------------------- > TIP 6: Have you searched our list archives? > > http://archives.postgresql.org >
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