Re: SELECT issue with references to different tables

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От Chris Angelico
Тема Re: SELECT issue with references to different tables
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Msg-id CAPTjJmrR1xseiS--od+0Y008ygbNMK_tgf0dqAsS4nnoUtEMGw@mail.gmail.com
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Ответ на SELECT issue with references to different tables  (Alexander Reichstadt <lxr@mac.com>)
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On Sun, Jun 3, 2012 at 4:50 AM, Alexander Reichstadt <lxr@mac.com> wrote:
> So, I have 4 tables
>
> pets
> persons
> companies
> pets_reference
>
> pets have owners, the owner at any point in time is either a persons or a company, never both at the same time.
>
> A pet owner can change to persons A, resulting in a record in pets_reference connecting pet and person with a
timestamp,setting refid_companies to zero and refid_persons to person A's record's id value. 

I'd use the SQL NULL value rather than zero here. You can then make
use of foreign key constraints easily.

> Now, the problem is with displaying a table with pets and only their current owners. I can't figure out two things.
> For one it seems I would need to somehow build a query which uses an if-then branch to check if companies is zero or
personsis zero to ensure to either reference a persons or a companies record. 
> The second issue is that I only need the max(ownersince) record, because I only need the current owner and not past
owners.

This sounds like a good job for an outer join. Something like this:

SELECT * from pets_reference JOIN pets ON (refid_pets = pets.id) LEFT
JOIN persons ON (refid_persons = persons.id) LEFT JOIN companies ON
(refid_companies = companies.id)

That will give you the pet record plus any associated person and/or
company data. When refid_companies is NULL, all fields that come from
the companies table will be NULL also (that's what the outer join
does).

The second issue is a little tricky to solve in standard SQL, and
there are various techniques that can be used. Here's one involving
Postgres's window functions:

SELECT refid_pets,first_value(ownersince) over
w,first_value(refid_persons) over w,first_value(refid_companies) over
w FROM pets_reference WINDOW w AS (partition refid_pets order by
ownersince desc)

I'm sure there's an easier way to do this, but I'm not an expert with
window functions.

Hope that helps!

Chris Angelico

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