Re: Split daterange into sub periods
| От | hmidi slim |
|---|---|
| Тема | Re: Split daterange into sub periods |
| Дата | |
| Msg-id | CAMsqVxtfzAcs3YGRJrTptC89DeF5U7o-8tzxfVknFB7a2PCx4g@mail.gmail.com обсуждение исходный текст |
| Ответ на | Re: Split daterange into sub periods (Andreas Kretschmer <andreas@a-kretschmer.de>) |
| Список | pgsql-general |
Based on you example I updated it to get the results that I want:
create table hmidi(
id serial primary key,
product_id integer,
d date range)
insert into hmidi(product_id, d) values(15, '[2018-11-01, 2018-11-01]');
insert into hmidi(product_id, d) values(15, '[2018-11-03, 2018-11-04]');
insert into hmidi(product_id, d) values(15, '[2018-11-03, 2018-11-04]');
Then I update you query:
with month as (
select distinct s::date, hmidi.product_id
from generate_series('2018-11-01'::date, '2018-11-05'::date,'1day'::interval) s
cross join hmidi
order by s::date
),
tmp as (
select month.s, month.product_id,
case when (hmidi.d @> month.s)
then 1
else null
end as covered
from month inner join hmidi on hmidi.product_id = month.product_id
group by month.product_id, month.s, hmidi.d, hmidi.product_id
),
tmp2 as (
select *,
coalesce((sum(case when covered = 1 then 1 else NULL end) over (partition by product_id order by s)) + 1,1) as p
from tmp
group by product_id,s, covered
)
select product_id,
daterange(min(s), max(s)) as range
from tmp2
where covered is null
and product_id = 15
group by p, product_id
with month as (
select distinct s::date, hmidi.product_id
from generate_series('2018-11-01'::date, '2018-11-05'::date,'1day'::interval) s
cross join hmidi
order by s::date
),
tmp as (
select month.s, month.product_id,
case when (hmidi.d @> month.s)
then 1
else null
end as covered
from month inner join hmidi on hmidi.product_id = month.product_id
group by month.product_id, month.s, hmidi.d, hmidi.product_id
),
tmp2 as (
select *,
coalesce((sum(case when covered = 1 then 1 else NULL end) over (partition by product_id order by s)) + 1,1) as p
from tmp
group by product_id,s, covered
)
select product_id,
daterange(min(s), max(s)) as range
from tmp2
where covered is null
and product_id = 15
group by p, product_id
I got these results:
15 "[2018-11-01,2018-11-02)"
15 "empty"
15 "[2018-11-04,2018-11-05)"
15 "empty"
15 "[2018-11-04,2018-11-05)"
However I should get:
15 "[2018-11-02, 2018-11-02]"
15 "[2018-11-05, 2018-11-05]"
I didn't master the usage of window functions such as 'over and partition'. I tried to resolve the problems by myself but no vain. Could you try to clarify me what is wrong with my query?
Thanks.
2018-07-05 16:39 GMT+01:00 Andreas Kretschmer <andreas@a-kretschmer.de>:
andreas@[local]:5432/test# \d hmidi
On 05.07.2018 15:49, hmidi slim wrote:Hi,I'm looking for splitting a daterange into many subperiods following this example:Base Date: [2018-01-01, 2018-01-31]overlapped_periods:1- [ 2018-01-04, 2018-01-06]2- [ 2018-01-09, 2018-01-12]3- [ 2018-01-18, 2018-01-19]I try to get such a result:
1- [ 2018-01-01, 2018-01-03]2- [ 2018-01-07, 2018-01-08]3- [ 2018-01-13, 2018-01-17]4- [ 2018-01-20, 2018-01-31]The operator '-' does not support this :
SELECT daterange('2018-01-01', '2018-01-31', '[]') - daterange('2018-01-04', '2018-01-06', '[]');I got this error:ERROR: result of range difference would not be contiguousIs there any operators to make the split of daterange?
Table "public.hmidi"
Column | Type | Collation | Nullable | Default
--------+-----------+-----------+----------+---------
id | integer | | not null |
d | daterange | | |
Indexes:
"hmidi_pkey" PRIMARY KEY, btree (id)
andreas@[local]:5432/test# insert into hmidi values (1,'[2018-01-04,2018-01-06]');INSERT 0 1
andreas@[local]:5432/test# insert into hmidi values (2,'[2018-01-09,2018-01-12]');INSERT 0 1
andreas@[local]:5432/test# insert into hmidi values (3,'[2018-01-18,2018-01-19]');INSERT 0 1
andreas@[local]:5432/test# with month as (select s::date from generate_series('2018-01-01'::date, '2018-01-31'::date,'1day':: interval) s), tmp as ( select month.s, case when hmidi.d @> month.s then 1 else NULL end as covered from month left join hmidi on month.s <@ hmidi.d),tmp2 as ( select *, coalesce((sum(case when covered = 1 then 1 else NULL end) over (order by s))+1,1) as p from tmp) select p, min(s), max(s) from tmp2 where covered is null group by p order by p;
p | min | max
----+------------+------------
1 | 2018-01-01 | 2018-01-03
4 | 2018-01-07 | 2018-01-08
8 | 2018-01-13 | 2018-01-17
10 | 2018-01-20 | 2018-01-31
(4 rows)
Regards, Andreas
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