Re: distinct estimate of a hard-coded VALUES list

Jeff Janes <jeff.janes@gmail.com> writes:
> So even though it knows that 6952 values have been shoved in the bottom, it
> thinks only 200 are going to come out of the aggregation.  This seems like
> a really lousy estimate.  In more complex queries than the example one
> given it leads to poor planning choices.

> Is the size of the input list not available to the planner at the point
> where it estimates the distinct size of the input list?  I'm assuming that
> if it is available to EXPLAIN than it is available to the planner.  Does it
> know how large the input list is, but just throw up its hands and use 200
> as the distinct size anyway?

It does know it, what it doesn't know is how many duplicates there are.

If we do what I think you're suggesting, which is assume the entries are
all distinct, I'm afraid we'll just move the estimation problems somewhere
else.