Re: Calling variadic function with default value in named notation

I too failed to realize that there was an implied, required, positional, parameter, of cardinality zero, following the named parameter.  I see no reason to make that case work.  I'm doubtful additional words in the documentation, examples or otherwise, would have helped people commit this edge case to memory.  The error message would be of benefit but IMO it isn't worth the effort given the sparsity of complaints and the assumed rarity that all three of these dynamics come into play in order to have an obscure doesn't work scenario.

David J.