Re: plperl syntax question

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От
David G. Johnston
Тема
Re: plperl syntax question
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CAKFQuwZa_k+7ZMrwksb+TGE9dP-mo1J9W1VHz7dSimA8cBFNEA@mail.gmail.com
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plperl syntax question stan <stanb@panix.com>
Re: plperl syntax question Rob Sargent <robjsargent@gmail.com>
Re: plperl syntax question "David G. Johnston" <david.g.johnston@gmail.com>
Re: plperl syntax question stan <stanb@panix.com>
Re: plperl syntax question Rob Sargent <robjsargent@gmail.com>
Re: plperl syntax question "David G. Johnston" <david.g.johnston@gmail.com>
Re: plperl syntax question "David G. Johnston" <david.g.johnston@gmail.com>
On Thursday, March 12, 2020, Rob Sargent <robjsargent@gmail.com> wrote:


On Mar 12, 2020, at 7:44 PM, stan <stanb@panix.com> wrote:

On Thu, Mar 12, 2020 at 06:37:02PM -0700, David G. Johnston wrote:
On Thursday, March 12, 2020, stan <stanb@panix.com> wrote:

my $rv3 = spi_exec_query('$stmt');
What am I doing wrong here?


Putting a variable name into a single-quoted string and expecting it to
resolve to the contents of said variable instead of being treated as a
literal.
David J.

Please look at this.

Here is the code:

my $stmt = qq('SELECT employee_key from employee where id = $user ;');
elog( NOTICE, "stmt = $stmt" );
my $rv3 = spi_exec_query($stmt);

So you fixed the error in the third line i and others pointed out but then decided to introduce a new error by changing the first line...

David J.


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