Fwd: PGAdmin cuts sql when show rules

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От Khushboo Vashi
Тема Fwd: PGAdmin cuts sql when show rules
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Msg-id CAFOhELdmupHpfE8MoZpG-ANbV14MpMLSARdPghxqb=PjJKdA6A@mail.gmail.com
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Ответ на PGAdmin cuts sql when show rules  (Мытарев Евгений <evmytarev@yandex.ru>)
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---------- Forwarded message ---------
From: Мытарев Евгений <evmytarev@yandex.ru>
Date: Wed, Aug 7, 2019 at 4:29 PM
Subject: Re: PGAdmin cuts sql when show rules
To: Khushboo Vashi <khushboo.vashi@enterprisedb.com>


Hey guys.

It is your project.

And honestly it is disgusting. I still can't get used to PGAdmin4 after using PGAdmin3.

And right now I found that It in addition gives incorrect information that I can't trust.

I do not have time to discover a hundreds of your maillists to find out which is specific for this bug.

I just want you to know that there is a serious problem in your programm. I think incorect SQL is a very serious.

If you don't interesting it, ok.

I definitely don’t need it

 
 
07.08.2019, 13:43, "Khushboo Vashi" <khushboo.vashi@enterprisedb.com>:
Hi,
 
On Wed, Aug 7, 2019 at 4:08 PM Мытарев Евгений <evmytarev@yandex.ru> wrote:
Hi,

I have a bug in 4.11.  It show rules sql incorrect.

 
 
Thanks,
Khushboo 
My rule is

CREATE OR REPLACE RULE replace_expression_answer AS
    ON INSERT TO dict.expression_answer
   WHERE (EXISTS ( SELECT 1
           FROM dict.expression_answer expression_answer_1
          WHERE expression_answer_1.id = new.id AND expression_answer_1.expression_id = new.expression_id)) DO INSTEAD  UPDATE dict.expression_answer SET header = new.header, condition = new.condition, formula = new.formula
  WHERE expression_answer.id = new.id AND expression_answer.expression_id = new.expression_id;



But in PGAdmin 4 I see only

CREATE OR REPLACE RULE replace_expression_answer AS
    ON INSERT TO dict.expression_answer
    WHERE expression_answer_1.id = new.id AND expression_answer_1.expression_id = new.expression_id))
    DO INSTEAD
UPDATE dict.expression_answer SET header = new.header, condition = new.condition, formula = new.formula
  WHERE expression_answer.id = new.id AND expression_answer.expression_id = new.expression_id;






 

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