Re: Redundant Result node
От | Ranier Vilela |
---|---|
Тема | Re: Redundant Result node |
Дата | |
Msg-id | CAEudQAp5Dwhpuj2278KfQdK6GnrZo5xg9h7X39ZSUOG9LuHsDg@mail.gmail.com обсуждение исходный текст |
Ответ на | Re: Redundant Result node (Rafia Sabih <rafia.pghackers@gmail.com>) |
Список | pgsql-hackers |
Hi Rafia.
Em qui., 22 de ago. de 2024 às 17:17, Rafia Sabih <rafia.pghackers@gmail.com> escreveu:
+1 for the idea of removing this redundant node.On Thu, 22 Aug 2024 at 15:02, Ranier Vilela <ranier.vf@gmail.com> wrote:Hi.Em qui., 22 de ago. de 2024 às 04:34, Richard Guo <guofenglinux@gmail.com> escreveu:I ran into a query plan where the Result node seems redundant to me:
create table t (a int, b int, c int);
insert into t select i%10, i%10, i%10 from generate_series(1,100)i;
create index on t (a, b);
analyze t;
set enable_hashagg to off;
set enable_seqscan to off;
explain (verbose, costs off)
select distinct b, a from t order by a, b;
QUERY PLAN
---------------------------------------------------------
Result
Output: b, a
-> Unique
Output: a, b
-> Index Only Scan using t_a_b_idx on public.t
Output: a, b
(6 rows)
What I expect is that both the Scan node and the Unique node output
'b, a', and we do not need an additional projection step, something
like:
explain (verbose, costs off)
select distinct b, a from t order by a, b;
QUERY PLAN
---------------------------------------------------
Unique
Output: b, a
-> Index Only Scan using t_a_b_idx on public.t
Output: b, a
(4 rows)
I looked into this a little bit and found that in function
create_ordered_paths, we decide whether a projection step is needed
based on a simple pointer comparison between sorted_path->pathtarget
and final_target.
/* Add projection step if needed */
if (sorted_path->pathtarget != target)
sorted_path = apply_projection_to_path(root, ordered_rel,
sorted_path, target);
This does not seem right to me, as PathTargets are not canonical, so
we cannot guarantee that two identical PathTargets will have the same
pointer. Actually, for the query above, the two PathTargets are
identical but have different pointers.Could memcmp solve this?With patch attached, using memcmp to compare the pointers.select distinct b, a from t order by a, b;
QUERY PLAN
----------------------------------
Sort
Output: b, a
Sort Key: t.a, t.b
-> HashAggregate
Output: b, a
Group Key: t.a, t.b
-> Seq Scan on public.t
Output: a, b, c
(8 rows)attached patch for consideration.best regards,Ranier VilelaI had a look in this patch, and I was wondering if we still need sorted_path->pathtarget != target in the condition.
Although the test is unnecessary, it is cheap and avoids a possible call to memcmp.
Thanks.
best regards,
Ranier Vilela
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