Re: Infinities in type numeric

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От Dean Rasheed
Тема Re: Infinities in type numeric
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Msg-id CAEZATCULz=LNg+jvmEhasLc2stvMeKX4izm9JC=z0xVhvHrA2w@mail.gmail.com
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Ответ на Infinities in type numeric  (Tom Lane <tgl@sss.pgh.pa.us>)
Ответы Re: Infinities in type numeric  (Tom Lane <tgl@sss.pgh.pa.us>)
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On Fri, 12 Jun 2020 at 02:16, Tom Lane <tgl@sss.pgh.pa.us> wrote:
>
> * I had to invent some semantics for non-standardized functions,
> particularly numeric_mod, numeric_gcd, numeric_lcm.  This area
> could use review to be sure that I chose desirable behaviors.
>

I think the semantics you've chosen for numeric_mod() are reasonable,
and I think they're consistent with POSIX fmod().

However, it looks like you've chosen gcd('Inf', x) = x, whereas I'd
say that the result should be 'NaN'.

One way to look at it is that the GCD result should exactly divide
both inputs with no remainder, but the remainder when you divide 'Inf'
by x is undefined, so you can't say that x exactly divides 'Inf'.

Another way to look at it is that gcd('Inf', x) is limit(n -> 'Inf',
gcd(n, x)), but that limit isn't well-defined. For example, suppose
x=10, then gcd('Inf', 10) = limit(n -> 'Inf', gcd(n, 10)), but gcd(n,
10) is either 1,2,5 or 10 depending on n, and it does not converge to
any particular value in the limit n -> 'Inf'.

A third way to look at it would be to apply one round of Euclid's
algorithm to it: gcd('Inf', x) = gcd(x, mod('Inf', x)) = gcd(x, 'NaN')
= 'NaN'.

Now you could argue that x=0 is a special case, and gcd('Inf', 0) =
'Inf' on the grounds that gcd(a, 0) = a for all finite 'a'. However, I
don't think that's particularly useful, and it fails the first test
that the result exactly divides both inputs because mod('Inf', 'Inf')
is undefined ('NaN').

Similar arguments apply to lcm(), so I'd say that both gcd() and lcm()
should return 'NaN' if either input is 'Inf' or 'NaN'.

Regards,
Dean



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