The subquery is going to return an intermediate result of:
V:A
---
2
And the minimum of that is 2, which is the wrong answer.
yes, you have true,
In above case wondering if we could do this
Min(a) = 2 is the condition, generate condition "a <= 2" and push it down as scan key. Since pushed down condition is lossy one for us ( it gives values < 2), finally do a recheck of "Min(a) = 2".
For Max(a) = 2 we can have "a >=2",
If both are given we can combine them appropriately.