Re: quoted csv to array pattern

On Wed, May 25, 2016 at 7:25 PM, Michael Moore <michaeljmoore@gmail.com> wrote:

I am trying to use

SELECT regexp_split_to_table('''quick brown'', ''fox'' ''over, dog''',  ','); 

I need the output to be:

quick brown
fox
over, dog

You cannot reliably/easily parse/split CSV with embedded delimiters using regex...you can cheat a bit if your data allows by making the delimiter <', '> instead of just <,>

David J.

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