Re: replacing expresion in plpgsql

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От Juan Pablo L
Тема Re: replacing expresion in plpgsql
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Msg-id CABSYDaby9-x3M2Xvd7NDHPGAO6x1t0w7K6Uc6ZwM6ejROi5K4A@mail.gmail.com
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Ответ на Re: replacing expresion in plpgsql  (Andreas Brandl <ml@3.141592654.de>)
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Hi i m working with timestamp cause i need the time too. i tried your solution and it works perfectly, it just does not adjust to my problem. thanks a lot for the answer.


On 15 December 2013 18:17, Andreas Brandl <ml@3.141592654.de> wrote:
Hi,

----- Ursprüngliche Mail -----
>
> Hi, i have a function that receives a parameter which represents
> days:
>
>
> FUNCTION aaa_recharge_account(expdays integer)
>
>
> i want to add those days to the CURRENT_DATE, but i do not know how
> to do it, i have tried several ways to replace that in an expresion
> like:

assuming you want to add expdays days to the CURRENT_DATE, you can just use + arithmetic of date:

# SELECT CURRENT_DATE + 5 as in_the_future_after_5_days;
 in_the_future_after_5_days
----------------------------
 2013-12-21
(1 row)

>
> newexpdate := CURRENT_TIMESTAMP + interval '$1 days' using expdays;
> (newexpdate is declared as timestamp)
>
>
> and many more but none work, can someone please help me to find out
> how can i replace that parameter into an expression that i can add
> to CURRENT_TIMESTAMP or any other way that i can accomplish what i
> need which is to add that parameter to the current timestamp.
> thanks!!!

Check this out:

# select current_timestamp, current_timestamp + interval '2' day;
              now              |           ?column?
-------------------------------+-------------------------------
 2013-12-16 01:16:19.783235+01 | 2013-12-18 01:16:19.783235+01
(1 row)

AFAIK that should also be SQL compliant.

Regards,
Andreas


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