Re: Get COUNT results from two different columns
От | Marc Olivé |
---|---|
Тема | Re: Get COUNT results from two different columns |
Дата | |
Msg-id | CAB7_X5wUaCWDhS698BfmuADJ5OmBuxssvPT_zvuD_4zkOfom7w@mail.gmail.com обсуждение исходный текст |
Ответ на | RE: Get COUNT results from two different columns ("Clive Swan" <cliveswan@gmail.com>) |
Список | pgsql-general |
SELECT new_sup, COUNT(new_sup)
FROM public."Data"
GROUP BY new_sup
) n
JOIN (
SELECT old_sup, COUNT(old_sup)
FROM public."Data"
GROUP BY old_sup
) o ON o.old_sup = n.new_sup -- I'm gessing this is the join condition you want
;
Regards,
Greetings,
I have two separate queries that work individually, returning a count from each column.
I want to subtract New(COUNT) from Old(Count)
I get an error when trying to run UNION?
I would appreciate any pointers.
-- COUNT NEW SUPPLIER
--
SELECT new_sup,
COUNT(new_sup)
FROM public."Data"
GROUP BY new_sup
This returns
Company_D 35
Company_E 30
Company_F 30
SELECT newld_sup,
COUNT(old_sup)
FROM public."Data"
GROUP BY old_sup
This returns
Company_A 1
Company_B 2
Company_D 35
Company_E 30
Company_F 30
SELECT new_sup, COUNT(new_sup) AS new_sup_count,
old_sup, COUNT(old_sup) AS old_sup_count
FROM
(
SELECT
new_sup, COUNT(new_sup) AS new_sup_count
FROM public."Data"
GROUP BY new_sup
UNION
SELECT
old_sup, COUNT(old_sup) AS old_sup_count
FROM public."Data"
GROUP BY old_sup
new_sup_count - old_sup_count
)
GROUP BY new_sup
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