Ingolf:
On Mon, Aug 23, 2021 at 2:39 PM Markhof, Ingolf
<ingolf.markhof@de.verizon.com> wrote:
> Yes, When I use (\1)? instead of (\1)+, the expression is evaluated quickly, but it doesn't return what I want. Once
aword is written, it is not subject to matching again. i.e.
> select regexp_replace( --> remove double entries
> 'one,one,one,two,two,three,three',
> '([^,]+)(,\1)?($|,)',
> '\1\3',
> 'g'
> ) as res;
>
...
> Honestly, this behaviour seems to be incorrect for me. Once the system replaces the first two 'one,one,' by a single
'one,',I'd expect to match this replaced one 'one,' with the next 'one,' following, replacing these two by another,
single'one,', again...
I think your expectation is misguided. All the regexp engines I've
used do it this way, when asked to match "g"lobally they do
non-overlapping matches, they do not substitute and recurse with the
modified string.
Also, your way opens the door to run-away or infinite loops (
rr('a','a','aa','g') or rr('a','a','a','g'), not to speak of
r('x','','','g') ). Even a misguided r(str, '_+','_','g'), used
sometimes to normalize space runs and similar things, can go into a
loop.
Francisco Olarte.