On Mon, Oct 17, 2011 at 11:54 PM, Tom Lane <tgl@sss.pgh.pa.us> wrote:
> Robert Haas <robertmhaas@gmail.com> writes:
>> - Why does the second byte need special handling for 0xED and 0xF4?
>
> http://www.faqs.org/rfcs/rfc3629.html
>
> See section 4 in particular. The underlying requirement is to disallow
> multiple representations of the same Unicode code point.
I'm still confused. The input string is already known to be valid
UTF-8, so the second byte (if there is one) must be between 0x80 and
0xBF. Therefore it will be neither 0xED nor 0xF4.
--
Robert Haas
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