Re: Using row_to_json with %ROWTYPE ?

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От Tim Smith
Тема Re: Using row_to_json with %ROWTYPE ?
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Msg-id CA+HuS5EKieCNabeo3mK4jhHopnjAzax3EQLvHbm69rfxemV=wQ@mail.gmail.com
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Ответ на Re: Using row_to_json with %ROWTYPE ?  (David Johnston <david.g.johnston@gmail.com>)
Ответы Re: Using row_to_json with %ROWTYPE ?  (Adrian Klaver <adrian.klaver@aklaver.com>)
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> So either PostgreSQL is seeing a different view (in a different schema) or the function is confused in ways difficult
topredict. 

Seriously ? You still want to continue calling it user-error ?  There
is no other view, there is no other schema , I am not hiding anything
from you !

On 5 February 2015 at 23:38, David Johnston <david.g.johnston@gmail.com> wrote:
> On Thu, Feb 5, 2015 at 4:29 PM, Tim Smith <randomdev4+postgres@gmail.com>
> wrote:
>>
>> You're most welcome to look at my view definition view if you don't
>> believe me ....
>>
>> View definition:
>>  SELECT a.session_id,
>>     a.session_ip,
>>     a.session_user_agent,
>>     a.session_start,
>>     a.session_lastactive,
>>     b.user_id,
>>     b.tenant_id,
>>     b.reseller_id,
>>     b.tenant_name,
>>     b.user_fname,
>>     b.user_lname,
>>     b.user_email,
>>     b.user_phone,
>>     b.user_seed,
>>     b.user_passwd,
>>     b.user_lastupdate,
>>     b.tenant_lastupdate
>>    FROM app_sessions a,
>>     app_users_vw b
>>   WHERE a.user_id = b.user_id;
>
>
> So that view and definition are correct.
>
> So either PostgreSQL is seeing a different view (in a different schema) or
> the function is confused in ways difficult to predict.
>
> I guess it is possible that:
>
> (SELECT v_row FROM v_row) would give that message but I get a "relation
> v_row does not exist" error when trying to replicate the scenario.
>
> It may even be a bug but since you have not provided a self-contained test
> case, nor the version of PostgreSQL, the assumption is user error.
>
> David J.
>


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