Ambiguous order by?

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От Cody Cutrer
Тема Ambiguous order by?
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Msg-id CA+=qeWu5+FUqkYz_Pi9a_LgVusLsep3mv54CGxZpirZ4g9bz-g@mail.gmail.com
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Ответы Re: Ambiguous order by?  (Tom Lane <tgl@sss.pgh.pa.us>)
Список pgsql-general
I'm not sure if this is a bug, or something I'm not understanding. When I have a column referenced in the select both fully qualified and not fully qualified, an explicit inner join, and that column in the order by (unqualified, and not in a function call), it complains that is ambiguous:

create table test1 (id integer, sortable_name varchar);
create table test2 (id integer, test1_id integer);
select test1.sortable_name, sortable_name from test1 inner join test2 on test1.id=test1_id order by sortable_name;
 
 
ERROR: ORDER BY "sortable_name" is ambiguous
LINE 1: ...t1 inner join test2 on test1.id=test1_id order by sortable_n...
 
All of these work:
 
select test1.sortable_name, sortable_name from test1 order by sortable_name /* no join */
select test1.sortable_name, sortable_name from test1, test2 where test1.id=test1_id order by sortable_name; /* implicit join */
select test1.sortable_name from test1 inner join test2 on test1.id=test1_id order by sortable_name /* only one sortable_name in select */
select test1.sortable_name, sortable_name from test1 inner join test2 on test1.id=test1_id order by test1.sortable_name /* qualify sortable_name in order, but not select */
select test1.sortable_name, test1.sortable_name from test1 inner join test2 on test1.id=test1_id order by sortable_name /* qualify sortable_name both selects */
select sortable_name, sortable_name from test1 inner join test2 on test1.id=test1_id order by sortable_name /* unqualified everywhere */
select test1.sortable_name, sortable_name from test1 inner join test2 on test1.id=test1_id order by substring(sortable_name,1,2); /* use a function in the order */


I've tried this on 9.1.4, 9.1.9, and 9.2.3.

The actual application usage looks more like SELECT users.*, sortable_name FROM users <single join and multiple where clauses> ORDER BY sortable_name. The application code always appends sortable_name to the select list because, depending on available features, sortable_name might be a function call and in a GROUP BY.

Thanks for any insight,

Cody Cutrer

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