Finding first free time from reservations table
| От | Andrus | 
|---|---|
| Тема | Finding first free time from reservations table | 
| Дата | |
| Msg-id | C4548EC84E8746E9B4BAA92310F1A4FE@dell2 обсуждение исходный текст  | 
		
| Ответы | 
                	
            		Re: Finding first free time from reservations table
            		
            		 | 
		
| Список | pgsql-general | 
I’m looking for a way to find first free time in reservations table.
Reservation table contains reservations start dates, start hours and durations.
Start hour is by half hour increments in working hours 8:00 .. 18:00 in work days.
Duration is also by half hour increments in day.
    CREATE TABLE reservation (
      id serial primary key,
      startdate date not null,  -- start date
      starthour numeric(4,1) not null , -- start hour 8 8.5 9 9.5  ..  16.5 17 17.5
      duration  Numeric(3,1) not null -- duration by hours 0.5 1 1.5 .. 9 9.5 10
    );
table structure can changed if required.
How to find first free half hour in table which is not reserved ?
E.q if table contains
    startdate   starthour  duration 
    14          9           1              -- ends at 9:59
    14          10          1.5            -- ends at 11:29, e.q there is 30 minute gap before next
    14          12          2
    14          16          2
result should be:
    starthour  duration
    11.5       0.5
Probably PostgreSql 9.2 window function should used to find 
first row whose starthour is greater than previous row starthour + duration  
How to write select statement which returns this information ?
Andrus.
I posted this also in 
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