Re: query with =ALL

Поиск
Список
Период
Сортировка
От Jaime Casanova
Тема Re: query with =ALL
Дата
Msg-id BAY8-F37FTJiby4wIaH00032e1d@hotmail.com
обсуждение исходный текст
Ответ на query with =ALL  ("Jaime Casanova" <el_vigia_ec@hotmail.com>)
Список pgsql-sql
>You're not expressing yourself clearly, because as far as I can
>understand you there are guaranteed to be no such results.
>
>            regards, tom lane

ok,

the output i want is equivalent to:

SELECT CPA.rub_codigo, RUB.rub_descripcion, CPA.cpa_valor, 
CPA.cpa_fechavencimiento
FROM rec_m_cuadropagos CPA, rec_m_rubro RUB
WHERE RUB.ent_codigo = CPA.ent_codigo AND RUB.rub_codigo = CPA.rub_codigo 
AND     CPA.ent_codigo = 1 AND CPA.sec_codigo = 1 AND CPA.ani_codigo = 
'2004-2005' AND     CPA.cic_codigo = 1 AND CPA.esp_codigo = 0 AND CPA.cur_codigo = 1 AND     CPA.cur_paralelo = 'A '
intersect
SELECT CPA.rub_codigo, RUB.rub_descripcion, CPA.cpa_valor, 
CPA.cpa_fechavencimiento
FROM rec_m_cuadropagos CPA, rec_m_rubro RUB
WHERE RUB.ent_codigo = CPA.ent_codigo AND RUB.rub_codigo = CPA.rub_codigo 
AND     CPA.ent_codigo = 1 AND CPA.sec_codigo = 1 AND CPA.ani_codigo = 
'2004-2005' AND     CPA.cic_codigo = 1 AND CPA.esp_codigo = 0 AND CPA.cur_codigo = 1 AND     CPA.cur_paralelo = 'B '
intersect
SELECT CPA.rub_codigo, RUB.rub_descripcion, CPA.cpa_valor, 
CPA.cpa_fechavencimiento
FROM rec_m_cuadropagos CPA, rec_m_rubro RUB
WHERE RUB.ent_codigo = CPA.ent_codigo AND RUB.rub_codigo = CPA.rub_codigo 
AND     CPA.ent_codigo = 1 AND CPA.sec_codigo = 1 AND CPA.ani_codigo = 
'2004-2005' AND     CPA.cic_codigo = 1 AND CPA.esp_codigo = 0 AND CPA.cur_codigo = 1 AND     CPA.cur_paralelo = 'C '

but i cannot use that solution because the columns in wich i want to so such 
type of query are various and depends on user input

_________________________________________________________________
Help STOP SPAM with the new MSN 8 and get 2 months FREE*  
http://join.msn.com/?page=features/junkmail



В списке pgsql-sql по дате отправления:

Предыдущее
От: Tom Lane
Дата:
Сообщение: Re: query with =ALL
Следующее
От: Stephan Szabo
Дата:
Сообщение: Re: query with =ALL