Re: sequence in schema -- broken default
| От | Lee Harr |
|---|---|
| Тема | Re: sequence in schema -- broken default |
| Дата | |
| Msg-id | BAY2-F136wB2iGb6Wkq0002f59c@hotmail.com обсуждение |
| Ответ на | sequence in schema -- broken default ("Lee Harr" <missive@hotmail.com>) |
| Ответы |
Re: sequence in schema -- broken default
|
| Список | pgsql-general |
>>CREATE DATABASE d;
>>\c d
>>
>>CREATE SCHEMA one;
>>SET search_path TO one;
>>
>>CREATE SEQUENCE foo_seq;
>>CREATE TABLE foo(
>> i integer
>> DEFAULT nextval('foo_seq')
>>);
>>
>>
>>SET search_path TO public;
>>
>>INSERT INTO foo VALUES (DEFAULT);
>
>>
>>The problem is that the DEFAULT nextval(... needs to qualify
>>the sequence with the schema, but I am not sure how to
>>determine the schema in my definition file.
>
>
>I am not sure I exactly understand the above paragraph, but from
>yourexample
>you are trying to insert into public.foo which does not exist. The value
>would be
>one.foo .
>
>insert into one.foo values();
Gah. Sorry.
That should have been ...
# set search_path to public;
SET
# INSERT INTO one.foo VALUES (DEFAULT);
ERROR: relation "foo_seq" does not exist
So, as you can see, since I specified the default as
nextval('foo_seq')
it does not find the sequence in my search_path.
It needs to be
nextval('one.foo_seq')
but I do not want to hard-code the name of the schema
in my database definition file if I can avoid it.
By the way... should the way you wrote it work?
# INSERT INTO one.foo VALUES ();
ERROR: syntax error at or near ")" at character 29
Seems like maybe it should work with the default, but I don't know.
# select version();
version
---------------------------------------------------------------------
PostgreSQL 7.4.1 on i386-portbld-freebsd4.9, compiled by GCC 2.95.4
_________________________________________________________________
STOP MORE SPAM with the new MSN 8 and get 2 months FREE*
http://join.msn.com/?page=features/junkmail
В списке pgsql-general по дате отправления: