Re: Help with SQL staterment
| От | Thom Brown |
|---|---|
| Тема | Re: Help with SQL staterment |
| Дата | |
| Msg-id | BANLkTikWtpu3UnSKQRrXqFAuWMFe9s9EQQ@mail.gmail.com обсуждение исходный текст |
| Ответ на | Re: Help with SQL staterment (Steve Crawford <scrawford@pinpointresearch.com>) |
| Ответы |
Re: Help with SQL staterment
|
| Список | pgsql-novice |
On 1 July 2011 00:23, Steve Crawford <scrawford@pinpointresearch.com> wrote:
> On 06/30/2011 04:04 PM, Thom Brown wrote:
>>
>> SELECT DISTINCT ON (contactkey)
>> paymentkey, contactkey, paymentdate
>> FROM
>> my_table
>> ORDER BY
>> contactkey, paymentdate DESC
>
> Gives the same result as my example but your solution is much cleaner.
Yes, I initially started thinking of some convoluted solution like:
WITH output_table AS
(
SELECT
first_value(paymentkey) OVER w paymentkey,
contactkey,
first_value(paymentdate) OVER w paymentdate
FROM
my_table
GROUP BY
paymentkey, contactkey
WINDOW w AS (PARTITION BY contactkey ORDER BY paymentdate DESC)
)
SELECT paymentkey, contactkey, paymentdate
FROM output_table
GROUP BY paymentkey, contactkey, paymentdate;
It will work, but it's massively over-complicated for this scenario. :)
--
Thom Brown
Twitter: @darkixion
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