Re: ordering of join using ON expression = any (array)

Hi,
is there a way to sort the joined tuples in the way they are in a the joined array ? BTW I'm using 8.4 (_I_ know I should upgrade, but management thinks we shouldn't :-( )
I'd like to join 2 tables based on a column, where the column is an array in one table, but I still need to keep the order of tuples as they were originally in the array.

What I now get is e.g. if the array contains A,B,C , I get rows B, C and A, but I'd like to get one row containing A, the B, then C

My query is:
select * from produkt inner join (select a_nr,komp as p_code from r_mi_sfm where a_nr=20110) as auftrag on (produkt.p_code = any(auftrag.p_code));

and explain says:
 Nested Loop  (cost=201.83..2656.51 rows=26992 width=98)
   Join Filter: ("inner".p_code = ANY ("outer".komp))
   ->  Index Scan using idx_r_mi_sfm_a_nr on r_mi_sfm  (cost=0.00..25.39 rows=7 width=58)
         Index Cond: (a_nr = 20110)
   ->  Materialize  (cost=201.83..278.95 rows=7712 width=40)
         ->  Seq Scan on produkt  (cost=0.00..194.12 rows=7712 width=40)

thanks for any input
Gerhard