Re: help with a simple SQL query
От | Obe, Regina DND\\MIS |
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Тема | Re: help with a simple SQL query |
Дата | |
Msg-id | B318FD8D29DCD411BD0500D0B7A91C67041041AF@jupiter обсуждение исходный текст |
Ответ на | help with a simple SQL query ("Andrew Stuart" <andrew.stuart@flatraterecruitment.com.au>) |
Список | pgsql-novice |
SELECT table2.* FROM table2 LEFT JOIN table1 ON table2.email = table1.email WHERE table1.email is null -----Original Message----- From: Andrew Stuart [mailto:andrew.stuart@flatraterecruitment.com.au] Sent: Wednesday, July 20, 2005 6:11 AM To: pgsql-novice@postgresql.org Subject: [NOVICE] help with a simple SQL query Hello I'm a newb. I'd love some help solving this apparently simple query. table one contains email sender addresses table two contains emails From table two I wish to SELECT all emails whose sender address is not in table one. Can anyone suggest how this might be done? Thanks in advance Andrew Stuart ---------------------------(end of broadcast)--------------------------- TIP 3: Have you checked our extensive FAQ? http://www.postgresql.org/docs/faq
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