Re: Like problem

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От Campbell, Lance
Тема Re: Like problem
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Msg-id B10E6810AC2A2F4EA7550D072CDE8760197EF4@SAB-FENWICK.sab.uiuc.edu
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Ответ на Re: Like problem  (Tom Lane <tgl@sss.pgh.pa.us>)
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Tom,
From your comments the recommended approach moving forward would be to
use ESCAPE and define your escape character?

Thanks for your help,

Lance Campbell
Project Manager/Software Architect
Web Services at Public Affairs
University of Illinois
217.333.0382
http://webservices.uiuc.edu

-----Original Message-----
From: Tom Lane [mailto:tgl@sss.pgh.pa.us]
Sent: Wednesday, February 13, 2008 10:53 AM
To: Richard Huxton
Cc: Campbell, Lance; pgsql-sql@postgresql.org
Subject: Re: [SQL] Like problem

Richard Huxton <dev@archonet.com> writes:
> Campbell, Lance wrote:
>> WARNING:  nonstandard use of escape in a string literal
>> LINE 1: ...ct c1 from t1 where c1 like '%abc\_%';

> Either indicate you are using an escaped string: LIKE E'%abc\_%'

Actually that's wrong, what he'd need is LIKE E'%abc\\_%'
(or omit the E and ignore the warning).

Alternatively, set standard_conforming_strings to TRUE and write
LIKE '%abc\_%' ... but beware that that might break other parts
of your app that are expecting backslash to be special.

> Or, change the escape character: LIKE '%abcQ_%' ESCAPE 'Q'

Yeah, this might be the easiest localized solution.
        regards, tom lane


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