Re: help needs in converting db2 function in postgresql.

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От Filip Rembiałkowski
Тема Re: help needs in converting db2 function in postgresql.
Дата
Msg-id AANLkTin3G7wXF0e8_ysFYP6zLYV-7=nt_FPBjzvj_vhe@mail.gmail.com
обсуждение исходный текст
Ответ на help needs in converting db2 function in postgresql.  ("Amar Dhole" <adhole@tibco.com>)
Ответы Re: help needs in converting db2 function in postgresql.  ("Amar Dhole" <adhole@tibco.com>)
Список pgsql-sql


2011/1/11 Amar Dhole <adhole@tibco.com>
Hi,
I need helping converting following db2 function in postgresql function.
Any pointer will be great help in proceeding me ahead.

CREATE FUNCTION in_liststring ( string CLOB(64K) )
  RETURNS TABLE ( ordinal INTEGER, index INTEGER )
  LANGUAGE SQL
  DETERMINISTIC
  NO EXTERNAL ACTION
  CONTAINS SQL
  RETURN
     WITH t(ordinal, index) AS
        ( VALUES ( 0, 0 )
          UNION ALL
          SELECT ordinal+1, COALESCE(NULLIF(
                    -- find the next delimiter ','
                    LOCATE(',', string, index+1), 0),
                    LENGTH(string)+1)
          FROM   t
                 -- to prevent a warning condition for infinite
                 -- recursions, we add the explicit upper
                 -- boundary for the &quot;ordinal&quot; values
          WHERE  ordinal < 10000 AND
                 -- terminate if there are no further delimiters
                 -- remaining
                 LOCATE(',', string, index+1) <> 0 )
     SELECT ordinal, index
     FROM   t
     UNION ALL
     -- add indicator for the end of the string
     SELECT MAX(ordinal)+1, LENGTH(string)+1
     FROM   t
;

commit;

DROP FUNCTION INSTRTBL;

CREATE FUNCTION INSTRTBL ( string CLOB(64K) )
  RETURNS TABLE ( INSTRTBL CLOB(64K) )
  LANGUAGE SQL
  DETERMINISTIC
  NO EXTERNAL ACTION
  CONTAINS SQL
  RETURN
     WITH t(ordinal, index) AS
        ( SELECT ordinal, index
          FROM   TABLE ( in_liststring(string) ) AS x )
     SELECT SUBSTR(string, t1.index+1, t2.index - t1.index - 1)
     -- the join below makes sure that we have the lower and
     -- upper index where we can find each of the ',' delimiters
     -- that are separating the INSTRTBL.  (For this, we exploit
     -- the additional indexes pointing to the beginning and end
     -- of the string.)
     FROM   t AS t1 JOIN t AS t2 ON
               ( t2.ordinal = t1.ordinal+1 )
;




create or replace function instrtbl(text)
returns table(instrtbl text)
language sql
immutable
strict
as $$
    SELECT * FROM regexp_split_to_table($1, ',')
$$;

filip@filip=# select * from instrtbl( 'one, two, really long three' );
      instrtbl      
--------------------
 one
  two
  really long three
(3 rows)

I love PostgreSQL.

Filip

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