Re: question about reg. expression

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От Stephen Belcher
Тема Re: question about reg. expression
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Msg-id AANLkTim9UYesBGU6fKf-sP6hcka8i45CyskKee9RPViJ@mail.gmail.com
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Ответ на Re: question about reg. expression  (Samuel Gendler <sgendler@ideasculptor.com>)
Ответы Re: question about reg. expression  (Kenneth Marshall <ktm@rice.edu>)
Список pgsql-sql
Another way to match multiple occurrences is to use curly brackets with a number, like:
select 'ab' ~ '^[a-z]{2}$';

It can be done with a range of numbers as well:
select 'ab' ~ '^[a-z]{2,4}$';
select 'abab' ~ '^[a-z]{2,4}$';

I believe, however, that the curly brackets notation was introduced in 9.0 and is not available in earlier versions.

--Stephen

On Wed, Jan 19, 2011 at 5:21 AM, Samuel Gendler <sgendler@ideasculptor.com> wrote:
I'd think you need to indicate multiple alphabetic matches.  Your first regex actually matches only b followed by end of string and the second is really only matching start of string followed by a.  The third is looking for a single character string.

Try this: select 'ab' ~ '^[a-z]+$'
or this: select 'ab' ~ '^[a-z]*$'

or if looking only for 2 character strings: select 'ab' ~ '^[a-z][a-z]$'


On Tue, Jan 18, 2011 at 3:41 PM, andrew1 <andrew1@mytrashmail.com> wrote:
hi all,

these return t:
select 'ab' ~ '[a-z]$'
select 'ab' ~ '^[a-z]'

select 'ab' ~ '^[a-z]$' returns f

Can't I use ^ and $ at the same time to match, in this case?
thanks.

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