On Tue, Nov 9, 2010 at 8:45 AM, Greg Stark <gsstark@mit.edu> wrote:
> But buffering the page only means you've got some consistent view of
> the page. It doesn't mean the checksum will actually match the data in
> the page that gets written out. So when you read it back in the
> checksum may be invalid.
I was assuming that if the code went through the trouble to buffer the
shared page to get a "stable, non-changing" copy to use for
checksumming/writing it, it would write() the buffered copy it just
made, not the original in shared memory... I'm not sure how that
write could be in-consistent.
a.
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aidan@highrise.ca command like a king,
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