Re: BUG #4648: needless deadlock on tables having foreign-key

Поиск
Список
Период
Сортировка
От Konstantin
Тема Re: BUG #4648: needless deadlock on tables having foreign-key
Дата
Msg-id 968596861.1234458088.55628440.14090@mcgi68.rambler.ru
обсуждение исходный текст
Ответ на Re: BUG #4648: needless deadlock on tables having foreign-key  (Tom Lane <tgl@sss.pgh.pa.us>)
Ответы Re: BUG #4648: needless deadlock on tables having foreign-key
Список pgsql-bugs
* Tom Lane <tgl@sss.pgh.pa.us> [Thu, 12 Feb 2009 10:54:34 -0500]:
> Heikki Linnakangas <heikki.linnakangas@enterprisedb.com> writes:
> > Hmm, the first UPDATE should've blocked already. It should've fired
a
> RI
> > trigger to lock the parent tuple in shared mode, but it looks like
> > that's not happening for some reason.
>
> Read the special code in AfterTriggerSaveEvent. This behavior is
> exactly what is expected --- since the referencing field didn't
> change, only the second update attempt actually fires the trigger.

Why? The second update is identical to the first one.
What is the difference? Such behavior looks very strange.

For example I wrote before to Heikki Linnakangas that I expect
parent tuple will not be lock if
a) foreign key is not modified explicitly at all
b) new value of foreign key is the same as old (not changed).

В списке pgsql-bugs по дате отправления:

Предыдущее
От: Tom Lane
Дата:
Сообщение: Re: BUG #4647: Geometric functions reorder their parameters randomly
Следующее
От: Heikki Linnakangas
Дата:
Сообщение: Re: BUG #4648: needless deadlock on tables having foreign-key