Re: SELECT duplicates in a table
| От | vhikida@inreach.com |
|---|---|
| Тема | Re: SELECT duplicates in a table |
| Дата | |
| Msg-id | 9211.146.74.1.99.1101146160.squirrel@146.74.1.99 обсуждение исходный текст |
| Ответ на | SELECT duplicates in a table ("Kall, Bruce A." <kall@mayo.edu>) |
| Ответы |
Re: SELECT duplicates in a table
|
| Список | pgsql-general |
Try
SELECT *
FROM mytable
WHERE (identification_number,date_of_birth) IN
(SELECT identification_number
, date_of_birth
FROM mytable m2
GROUP BY identification_number,data_of_birth
HAVING COUNT(*) > 1
)
There are other ways of doing it, perhaps more efficient.
Vincent
> I've look for a solution to this, but have only been able to find
> solutions to delete duplicate entries in a table by deleting entries not
> returned by SELECT DISTINCT.
>
> What sql should I use to SELECT entries in a table that have two
> particular column values that match?
>
> For example, my_table has
> name, phone number, identification_number, zip code, date of birth, and
> city
>
> I want to SELECT rows from this table that have the same values in
> identification and date of birth (duplicates) so I can have the user
> look at them in order to figure out which one to delete.
>
> I tried something like:
>
> $db_sql = "SELECT * FROM my_table GROUP BY identification_number
> HAVING count(date_of_birth) > 1 ORDER BY name"
>
> but that doesn't seem to work.
>
> Thanks,
> Bruce
>
>
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