Re: SELECT duplicates in a table

Поиск
Список
Период
Сортировка
От vhikida@inreach.com
Тема Re: SELECT duplicates in a table
Дата
Msg-id 9211.146.74.1.99.1101146160.squirrel@146.74.1.99
обсуждение исходный текст
Ответ на SELECT duplicates in a table  ("Kall, Bruce A." <kall@mayo.edu>)
Ответы Re: SELECT duplicates in a table  ("Kall, Bruce A." <kall@mayo.edu>)
Список pgsql-general
Try

SELECT *
  FROM mytable
 WHERE (identification_number,date_of_birth) IN
          (SELECT identification_number
                , date_of_birth
             FROM mytable m2
            GROUP BY identification_number,data_of_birth
           HAVING COUNT(*) > 1
          )

There are other ways of doing it, perhaps more efficient.

Vincent

> I've look for a solution to this, but have only been able to find
> solutions to delete duplicate entries in a table by deleting entries not
> returned by SELECT DISTINCT.
>
> What sql should I use to SELECT entries in a table that have two
> particular column values that match?
>
> For example, my_table has
> name, phone number, identification_number, zip code, date of birth, and
> city
>
> I want to SELECT rows from this table that have the same values in
> identification and date of birth (duplicates) so I can have the user
> look at them in order to figure out which one to delete.
>
> I tried something like:
>
>   $db_sql = "SELECT * FROM my_table GROUP BY identification_number
> HAVING count(date_of_birth) > 1 ORDER BY name"
>
> but that doesn't seem to work.
>
> Thanks,
> Bruce
>
>
> ---------------------------(end of broadcast)---------------------------
> TIP 6: Have you searched our list archives?
>
>                http://archives.postgresql.org
>



В списке pgsql-general по дате отправления:

Предыдущее
От: "Kall, Bruce A."
Дата:
Сообщение: SELECT duplicates in a table
Следующее
От: "Kall, Bruce A."
Дата:
Сообщение: Re: SELECT duplicates in a table