When I make the following simplified example:
SELECT regexp_matches('<img src="wwww" title="dit is een title tekst" class="class12">'
,'((title\s*=\s*\"([^"]*)")+)|((src\s*=\s*\"([^"]*)")+)','ig')
My result are 2 rows:
"{NULL,NULL,NULL,"src=\"wwww\"","src=\"wwww\"",wwww}"
"{"title=\"dit is een title tekst\"","title=\"dit is een title tekst\"","dit is een title tekst",NULL,NULL,NULL}"
I would like to have 1 row which contains both the records. Does anyone know how I can solve this?
Van: pgsql-general-owner@postgresql.org [mailto:pgsql-general-owner@postgresql.org] Namens WP Perquin
Verzonden: dinsdag 12 mei 2009 13:44
Aan: pgsql-general@postgresql.org
Onderwerp: [GENERAL] regexp_matches problem
(postgresql 8.3.7, linux centos)
I made the following regexp_matches
SELECT regexp_matches(
(
SELECT content
FROM page
WHERE idpage = 2
)
,','<img\\s+((title="[^"]+")|(alt="[^"]+")|([^>]))*>'
, 'ig'
) AS result
The result looks like: {"\"",NULL,NULL,"\""} in phpPgAdmin.
Which is not the right result. I want to see als the images and their alt, title and src.
Can anyone help with telling what I am doing wrong?
Willem