Re: Subcribing to this list, what's the secret?

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От Ian Harding
Тема Re: Subcribing to this list, what's the secret?
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Msg-id 725602300612140847q1676108w1cf58c1ec86e345d@mail.gmail.com
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Ответ на Subcribing to this list, what's the secret?  (wheel <wheel@wheel.not>)
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If you have a dot in your gmail username, take it out.  Gmail ignores
it and validation scripts often puke on it.

Then use that email as your reply to, not some nonexistent carp.

- Ian

On 12/13/06, wheel <wheel@wheel.not> wrote:
> I seem to have a natural knack for hitting the ruts around here, which
> is exciting. I've tried to subscribe to the list using both yahoo and
> gmail email accounts and the webform always reports "The email address
> you entered does not appear to be valid." I would like to use either
> yahoo or gmail because I am very interested in keeping spam down on my
> main email accounts (see Jan 7 2006 thread 'E-mail harvesting on PG
> lists?'). I've been posting via a newsreader but it seems that there is
> some strange pattern with messages not making it on the the list using
> that pipe...all of my posts show on the google archive of this list but
> a good number (25%?) seem to be missing from the mailing list archives
> that are found on the postgres site. Example, it seems that both of my
> responses to Scott Marlowe never made it to the list, but are somehow
> listed in google, and on the newsgroup. Scott was PO'd that I didn't
> respond to his first post, that got me to check into why he didn't.
>
> I posted about this issue, the failure of the website subscription form
> to accept (at least) an @yahoo.com email acct, and no one replied
> (though that was one of the posts that didnt' seem to make it onto the
> mailing list, but is on google & newsgroup). Can someone tell me what
> the secret is, or check the webform at postgresql.org and make sure it's
> in order?
>
> ---------------------------(end of broadcast)---------------------------
> TIP 4: Have you searched our list archives?
>
>                http://archives.postgresql.org/
>

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