Re: Regression in Postgres 17?

On 10/22/24 08:54, Colin 't Hart wrote:
> Hi,
> 
> This works in Postgres 15:
> 
> pg15> create function json_test(out value text, out json jsonb)
> returns record
> language sql
> as
> $$
>    select null::text, null::jsonb;
> $$
> ;
> CREATE FUNCTION
> pg15> select * from json_test();
> ┌───────┬──────┐
> │ value │ json │
> ├───────┼──────┤
> │       │      │
> └───────┴──────┘
> (1 row)
> 
> 
> In Postgres 17 trying to create the function yields an error:
> 
> pg17> create function json_test(out value text, out json jsonb)
> returns record
> language sql
> as
> $$
>    select null::text, null::jsonb;
> $$
> ;
> ERROR:  syntax error at or near "jsonb"
> LINE 1: create function json_test(out value text, out json jsonb)
> 
> 
> Am I doing something wrong? Or is this a regression?

Yes you are doing something wrong, naming an argument with a type 
name(json) is not a good idea. Guessing you got caught by this:

https://www.postgresql.org/docs/16/sql-keywords-appendix.html

JSON     non-reserved     reserved           

https://www.postgresql.org/docs/17/sql-keywords-appendix.html

JSON     non-reserved (cannot be function or type)     reserved           



> Thanks,
> 
> Colin

-- 
Adrian Klaver
adrian.klaver@aklaver.com