Re: question about join

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От Osvaldo Kussama
Тема Re: question about join
Дата
Msg-id 690707f60805010817x4b541a82i22bdd3ec87261717@mail.gmail.com
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Ответ на question about join  (Ottavio Campana <ottavio@campana.vi.it>)
Ответы Re: question about join
Список pgsql-general
2008/5/1 Ottavio Campana <ottavio@campana.vi.it>:
> Hi, I'm having a problem trying to write a query using join, and I hope you
> can give me a hint.
>
>  suppose you have a three tables like these:
>
>  create table first_table (
>         id serial primary key,
>         description1 text);
>
>  create table second_table (
>         id serial primary key,
>         description2 text);
>
>  create table third_table (
>         id serial primary key,
>         description3 text,
>         id_ref_first_tab integer references first_table(id),
>         id_ref_second_tab integer references second_table(id),
>         default_value boolean);
>
>  create unique index idx1 on third_table
> (id_ref_first_tab,id_ref_second_tab);
>
>  create unique index idx2 on third_table (id_ref_second_tab) where
> default_value = true;
>
>  What I'm trying to do is joining the second and the third tables on
> second_table.id = third_table.id_ref_second_tab to extract all the values in
> third_table where id_ref_first_tab has a given value or, in case it is not
> present, to extract only row that has default_values = true;
>
>  To further explain, the following query selects both the rows from the join
> where id_ref_first_tab has the desired value and default_value = true, while
> I want to select the row corresponding to default_value = true only in case
> no row corresponding to id_ref_first_tab exists.
>
>  select * from second_table join third_table on second_table.id =
> third_table.id_ref_second_tab where id_ref_first_tab = 1 or default_value =
> true;
>
>  I hope I've been clear enough...
>


Try:
select * from second_table join third_table on second_table.id =
third_table.id_ref_second_tab
where id_ref_first_tab = 1 or (id_ref_first_tab <> 1 and default_value = true);

Osvaldo

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