Re: [HACKERS] asynchronous execution

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От Antonin Houska
Тема Re: [HACKERS] asynchronous execution
Дата
Msg-id 6448.1499761731@localhost
обсуждение исходный текст
Ответ на Re: [HACKERS] asynchronous execution  (Kyotaro HORIGUCHI <horiguchi.kyotaro@lab.ntt.co.jp>)
Ответы Re: [HACKERS] asynchronous execution  (Kyotaro HORIGUCHI <horiguchi.kyotaro@lab.ntt.co.jp>)
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Kyotaro HORIGUCHI <horiguchi.kyotaro@lab.ntt.co.jp> wrote:

> > Just one idea that I had while reading the code.
> >
> > In ExecAsyncEventLoop you iterate estate->es_pending_async, then move the
> > complete requests to the end and finaly adjust estate->es_num_pending_async so
> > that the array no longer contains the complete requests. I think the point is
> > that then you can add new requests to the end of the array.
> >
> > I wonder if a set (Bitmapset) of incomplete requests would make the code more
> > efficient. The set would contain position of each incomplete request in
> > estate->es_num_pending_async (I think it's the myindex field of
> > PendingAsyncRequest). If ExecAsyncEventLoop used this set to retrieve the
> > requests subject to ExecAsyncNotify etc, then the compaction of
> > estate->es_pending_async wouldn't be necessary.
> >
> > ExecAsyncRequest would use the set to look for space for new requests by
> > iterating it and trying to find the first gap (which corresponds to completed
> > request).
> >
> > And finally, item would be removed from the set at the moment the request
> > state is being set to ASYNCREQ_COMPLETE.
>
> Effectively it is a waiting-queue followed by a
> completed-list. The point of the compaction is keeping the order
> of waiting or not-yet-completed requests, which is crucial to
> avoid kind-a precedence inversion. We cannot keep the order by
> using bitmapset in such way.

> The current code waits all waiters at once and processes all
> fired events at once. The order in the waiting-queue is
> inessential in the case. On the other hand I suppoese waiting on
> several-tens to near-hundred remote hosts is in a realistic
> target range. Keeping the order could be crucial if we process a
> part of the queue at once in the case.
>
> Putting siginificance on the deviation of response time of
> remotes, process-all-at-once is effective. In turn we should
> consider the effectiveness of the lifecycle of the larger wait
> event set.

ok, I missed the fact that the order of es_pending_async entries is
important. I think this is worth adding a comment.

Actually the reason I thought of simplification was that I noticed small
inefficiency in the way you do the compaction. In particular, I think it's not
always necessary to swap the tail and head entries. Would something like this
make sense?

    /* If any node completed, compact the array. */    if (any_node_done)    {        int        hidx = 0,
 tidx; 
        /*         * Swap all non-yet-completed items to the start of the array.         * Keep them in the same order.
       */        for (tidx = 0; tidx < estate->es_num_pending_async; ++tidx)        {            PendingAsyncRequest
*tail= estate->es_pending_async[tidx]; 
            Assert(tail->state != ASYNCREQ_CALLBACK_PENDING);
            if (tail->state == ASYNCREQ_COMPLETE)                continue;
            /*             * If the array starts with one or more incomplete requests,             * both head and tail
pointat the same item, so there's no             * point in swapping.             */            if (tidx > hidx)
   {                PendingAsyncRequest *head = estate->es_pending_async[hidx]; 
                /*                 * Once the tail got ahead, it should only leave                 * ASYNCREQ_COMPLETE
behind.Only those can then be seen                 * by head.                 */                Assert(head->state ==
ASYNCREQ_COMPLETE);
                estate->es_pending_async[tidx] = head;                estate->es_pending_async[hidx] = tail;
}
            ++hidx;        }
        estate->es_num_pending_async = hidx;    }

And besides that, I think it'd be more intuitive if the meaning of "head" and
"tail" was reversed: if the array is iterated from lower to higher positions,
then I'd consider head to be at higher position, not tail.

--
Antonin Houska Cybertec Schönig & Schönig GmbH Gröhrmühlgasse 26 A-2700 Wiener
Neustadt Web: http://www.postgresql-support.de, http://www.cybertec.at



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