Re: SUBSTRING for a regular expression
От | |
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Тема | Re: SUBSTRING for a regular expression |
Дата | |
Msg-id | 61854.216.238.112.88.1089293215.squirrel@$HOSTNAME обсуждение исходный текст |
Ответ на | SUBSTRING for a regular expression (<btober@computer.org>) |
Ответы |
Re: SUBSTRING for a regular expression
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Список | pgsql-general |
> >> I was hopeful that this would work, since I had missed the need to >> double the back-slash escape character in my original work, but >> something still isn't right. >> >> First I got an error message that psql didn't like the "?" characters >> in the RE, so I eliminated them and wrote > > > Sounds like you may be using an older version of Pg than me. What > version are you running? Only that can tell us how limiting your regex > capabilitites are.... Not that old (I think)! crime=# select version(); version -------------------------------------------------------------------------------- ----------------------------------------------- PostgreSQL 7.3.4 on i386-redhat-linux-gnu, compiled by GCC i386-redhat-linux-gc c (GCC) 3.2.2 20030222 (Red Hat Linux 3.2.2-5) (1 row) --Berend Tober
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