Re: getting last day of month
| От | Chris Browne |
|---|---|
| Тема | Re: getting last day of month |
| Дата | |
| Msg-id | 60r7chn22e.fsf@dba2.int.libertyrms.com обсуждение |
| Ответ на | getting last day of month (Sergey Pariev <egy@tnet.dp.ua>) |
| Список | pgsql-general |
egy@tnet.dp.ua (Sergey Pariev) writes:
> I need to find out the last day of current month. Currently I do the
> trick with code below, but that's rather ugly way to do it IMHO. Could
> anybody suggest me a better way ?
log_analysis=# select date_trunc('months', (date_trunc('months', now()) + '45 days'::interval)) - '1 day'::interval;
?column?
------------------------
2005-08-31 00:00:00+00
(1 row)
So...
log_analysis=# create or replace function eom (timestamptz) returns timestamptz as '
log_analysis'# select date_trunc(''months'', (date_trunc(''months'', $1) + ''45 days''::interval)) - ''1
day''::interval;'language sql;
CREATE FUNCTION
log_analysis=# select eom(now());
eom
------------------------
2005-08-31 00:00:00+00
(1 row)
log_analysis=# select eom('2004-07-02');
eom
------------------------
2004-07-31 00:00:00+00
(1 row)
log_analysis=# select eom('2004-02-29');
eom
------------------------
2004-02-29 00:00:00+00
(1 row)
log_analysis=# select eom('2004-02-29'), eom('2005-02-28'), eom('2005-03-01');
eom | eom | eom
------------------------+------------------------+------------------------
2004-02-29 00:00:00+00 | 2005-02-28 00:00:00+00 | 2005-03-31 00:00:00+00
(1 row)
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