Re: Column-Level Privileges

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От Robert Haas
Тема Re: Column-Level Privileges
Дата
Msg-id 603c8f070902031618j3029da75wcc2f9fc8846732d@mail.gmail.com
обсуждение исходный текст
Ответ на Re: Column-Level Privileges  (Tom Lane <tgl@sss.pgh.pa.us>)
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On Tue, Feb 3, 2009 at 7:04 PM, Tom Lane <tgl@sss.pgh.pa.us> wrote:
> Stephen Frost <sfrost@snowman.net> writes:
>> * Tom Lane (tgl@sss.pgh.pa.us) wrote:
>>> * Some of the information_schema views are specified to respond to
>>> per-column privileges; the column_privileges and columns views
>>> certainly need work now to meet spec, and there might be others.
>
>> Done.
>
> I looked through the spec a bit.  If I'm reading it right, these
> views should show columns that you have either table-level or
> column-level privilege for:
>        column_privileges
>        columns
>        key_column_usage
>        role_column_grants
>
> What's more, these views should show you tables/views that you have
> column privilege on any column of, even if you haven't got any
> full-table privileges:
>        tables
>        table_constraints
>        table_privileges
>        views
>
> I thought about handling the tests for the latter by exposing
> pg_attribute_aclcheck_all() as a function named something like
> has_any_column_privilege().  However, that would amount to forcing a
> nestloop-with-inner-indexscan join to pg_attribute for any table you
> didn't have full-table privileges for; also it would bloat the syscache
> in a database with lots of tables.  It might be better to expose that
> join explicitly and let the planner try to decide what to do.  OTOH
> I don't think the planner would be very smart about avoiding the join
> if you do have full-table privileges.  Either way you slice it it could
> be really slow :-(
>
> Comments, better ideas?  Does anyone think I misread the spec?

Perhaps there should be a column in pg_class that indicates, in
essence, whether there is any point in checking pg_attribute. Call it
relaclpartial aclitem[].  Whenever user U has column-level privileges
P and Q on a subset of the columns in the table, put {U=PQ} in
relaclpartial.

...Robert


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