Re: Create interval using column value?

Thanks, that was exactly what I needed.

Larry

]At 11:11 PM 10/24/2004, Tom Lane wrote:
>Larry Lennhoff  writes:
> > What I want to do is find all the rows in
> > A which were built before now() - build_interval seconds ago.  If I could
> > just write this in SQL it would look something like:
>
> > SELECT A.id FROM A JOIN B ON (join_col) WHERE built_on < now() - interval
> > 'build_interval seconds';
>
>You are confused about the difference between a literal constant and an
>expression.   Try something like
>
>.. WHERE built_on < now() - build_interval * interval '1 second';
>
>which relies on the number-times-interval operator.
>
>                         regards, tom lane