Re: [PATCH] Support SK_SEARCHNULL / SK_SEARCHNOTNULL for heap-only scans

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От Jacob Champion
Тема Re: [PATCH] Support SK_SEARCHNULL / SK_SEARCHNOTNULL for heap-only scans
Дата
Msg-id 5a8f60f7-d2dc-d781-5709-cda5ab7a0064@timescale.com
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Ответ на Re: [PATCH] Support SK_SEARCHNULL / SK_SEARCHNOTNULL for heap-only scans  (Jacob Champion <jchampion@timescale.com>)
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On 7/19/23 16:44, Jacob Champion wrote:
> This patch pushes down any
> forced-null and not-null Vars as ScanKeys. It doesn't remove the
> redundant quals after turning them into ScanKeys, so it's needlessly
> inefficient, but there's still a decent speedup for some of the basic
> benchmarks in 0003.
> 
> Plans look something like this:
> 
> # EXPLAIN SELECT * FROM t WHERE i IS NULL;
>                          QUERY PLAN
> ------------------------------------------------------------
>  Seq Scan on t  (cost=0.00..1393.00 rows=49530 width=4)
>    Scan Cond: (i IS NULL)
>    Filter: (i IS NULL)
> (3 rows)

Redundant clauses are now filtered out in v3. So the new plans look more
like what you'd expect:

  =# EXPLAIN SELECT * FROM table1 WHERE a IS NOT NULL AND b = 2;
                         QUERY PLAN
  ---------------------------------------------------------
   Seq Scan on table1  (cost=0.00..3344.00 rows=1 width=4)
     Scan Cond: (a IS NOT NULL)
     Filter: (b = 2)
  (3 rows)

> The non-nullable case worries me a bit because so many things imply IS
> NOT NULL. I think I need to do some sort of cost analysis using the
> null_frac statistics -- it probably only makes sense to push an
> implicit SK_SEARCHNOTNULL down to the AM layer if some fraction of
> rows would actually be filtered out -- but I'm not really sure how to
> choose a threshold.

v3 also uses the nullfrac and the expected cost of the filter clauses to
decide whether to promote a derived IS NOT NULL condition to a ScanKey.
(Explicit IS [NOT] NULL clauses are always promoted.) I'm still not sure
how to fine-tune the expected cost of the ScanKey, but the number I've
chosen for now (`0.1 * cpu_operator_cost`) doesn't seem to regress my
benchmarks, for whatever that's worth.

I recorded several of the changes to the regression EXPLAIN output, but
I've left a few broken because I'm not sure if they're useful or if I
should just disable the optimization. For example:

   explain (analyze, costs off, summary off, timing off)
     select * from list_part where a = list_part_fn(1) + a;
                               QUERY PLAN
   ------------------------------------------------------------------
    Append (actual rows=0 loops=1)
      ->  Seq Scan on list_part1 list_part_1 (actual rows=0 loops=1)
  +         Scan Cond: (a IS NOT NULL)
            Filter: (a = (list_part_fn(1) + a))
            Rows Removed by Filter: 1
      ->  Seq Scan on list_part2 list_part_2 (actual rows=0 loops=1)
  +         Scan Cond: (a IS NOT NULL)
            Filter: (a = (list_part_fn(1) + a))
            Rows Removed by Filter: 1
      ->  Seq Scan on list_part3 list_part_3 (actual rows=0 loops=1)
  +         Scan Cond: (a IS NOT NULL)
            Filter: (a = (list_part_fn(1) + a))
            Rows Removed by Filter: 1
      ->  Seq Scan on list_part4 list_part_4 (actual rows=0 loops=1)
  +         Scan Cond: (a IS NOT NULL)
            Filter: (a = (list_part_fn(1) + a))
            Rows Removed by Filter: 1

These new conditions are due to a lack of statistics for the tiny
partitions; the filters are considered expensive enough that the savings
against a DEFAULT_UNK_SEL proportion of NULLs would hypothetically be
worth it. Best I can tell, this is a non-issue, since autovacuum will
fix the problem by the time the table grows to the point where the
pointless ScanKey would cause a slowdown. But it sure _looks_ like a
mistake, especially since these particular partitions can't even contain
NULL. Do I need to do something about this short-lived case?

There's still other work to do -- for instance, I think my modifications
to the filter clauses have probably broken some isolation levels until I
fix up SeqRecheck(), and better benchmarks would be good -- but I think
this is ready for early CF feedback.

Thanks,
--Jacob
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