On 12/29/19 02:30, Fabien COELHO wrote:
>>> C modulo operator (%) is a pain because it is not positive remainder
>>> (2 % -3 == -1 vs 2 % 3 == 2, AFAICR).
>>
>> This does not seem to be the case...
> ...
> Because I do not trust C modulo as I had a lot of problems with it? :-)
If I recall correctly (and I'm traveling and away from those notes),
the exact semantics of C's % with negative operands was left
implementation-defined until, was it, C99 ?
So it might be ok to rely on the specified C99 behavior (whichever
behavior that is, he wrote, notelessly) for PG 12 and later, where
C99 is expected.
Regards,
-Chap