Re: [HACKERS] An optimisation question

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От Tom Lane
Тема Re: [HACKERS] An optimisation question
Дата
Msg-id 5561.936023612@sss.pgh.pa.us
обсуждение исходный текст
Ответ на An optimisation question  (Constantin Teodorescu <teo@flex.ro>)
Список pgsql-hackers
Constantin Teodorescu <teo@flex.ro> writes:
> select data from valori order by desc limit 1
> NOTICE:  QUERY PLAN:
> Sort  (cost=3216.01 rows=72970 width=8)
-> Seq Scan on valori  (cost=3216.01 rows=72970 width=8)

> I thought that if the 'order by' implies an column which have a btree
> index, the sort would not be actually executed and the index will be
> used instead. But it seems that it won't.

That's fixed for 6.6.  A workaround that partially solves the problem
for 6.5 is to add a dummy WHERE clause referencing the ORDER-BY item:select data from valori where data >
'1/1/1800'orderby data limit 1;
 
The WHERE is needed to get the 6.5 optimizer to consider the index
at all.  In a quick test it seems this works for normal order but not
DESC order... you could try applying the backwards-index patch that
someone (Hiroshi or Tatsuo, I think) posted recently.

> Also, the following query :
> select max(data) from valori where data<'2-3-1999'
> is not using optimally the index, it just limit the records for the
> aggregate function instead of picking the first value from the left of
> the index tree lower than '2-3-1999'.

There's no prospect of that happening anytime soon, I fear; there is no
connection between aggregate functions and indexes in the system, and
no easy way of making one.  This workaround works in current sources:

explain select data from valori where data<'2-3-1999'
order by data desc limit 1;
NOTICE:  QUERY PLAN:

Index Scan Backward using valori_i on valori  (cost=21.67 rows=334 width=8)
        regards, tom lane


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