Re: RfD: more powerful "any" types

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От Tom Lane
Тема Re: RfD: more powerful "any" types
Дата
Msg-id 5434.1252524232@sss.pgh.pa.us
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Ответ на Re: RfD: more powerful "any" types  (Robert Haas <robertmhaas@gmail.com>)
Ответы Re: RfD: more powerful "any" types  (Sam Mason <sam@samason.me.uk>)
Re: RfD: more powerful "any" types  (Robert Haas <robertmhaas@gmail.com>)
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Robert Haas <robertmhaas@gmail.com> writes:
> What we need is a system where base types are represented
> by an OID, but derived types (list and functional types) are built up
> using type constructors that take other types as arguments.

This is SQL, not Haskell.  What you suggest seems about two orders of
magnitude more complex than real-world applications could justify.

(so where is pl/haskell, anyway?)
        regards, tom lane


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