Nick wrote:
> I have a pretty well tuned setup, with appropriate indexes and 16GB of
> available RAM. Should this be taking this long? I forced it to not use
> a sequential scan and that only knocked a second off the plan.
>
> QUERY
> PLAN
>
------------------------------------------------------------------------------------------------------------------------------------------
> Hash Right Join (cost=105882.35..105882.47 rows=3 width=118) (actual
> time=3931.567..3931.583 rows=4 loops=1)
> Hash Cond: (songs_downloaded.advertisement_id = a.id)
> -> HashAggregate (cost=105881.21..105881.26 rows=4 width=13)
> (actual time=3931.484..3931.489 rows=3 loops=1)
> -> Seq Scan on songs_downloaded (cost=0.00..95455.96
> rows=1042525 width=13) (actual time=0.071..1833.680 rows=1034752
> loops=1)
> Filter: (advertiser_id = 6553406)
> -> Hash (cost=1.10..1.10 rows=3 width=46) (actual
> time=0.050..0.050 rows=4 loops=1)
> Buckets: 1024 Batches: 1 Memory Usage: 1kB
> -> Seq Scan on advertisements a (cost=0.00..1.10 rows=3
> width=46) (actual time=0.037..0.041 rows=4 loops=1)
> Filter: (advertiser_id = 6553406)
> Total runtime: 3931.808 ms
> (10 rows)
What indexes do you have? Can you show some?
I bet you need something like (advertiser_id, advertisement_id), because
plain index would not be sorted right.
> SELECT a.id, sd.price, COALESCE(sd.downloads,0) AS downloads,
> COALESCE(sd.download_revenue,0) AS download_revenue
> FROM advertisements a
> LEFT JOIN (SELECT advertisement_id, AVG(price) AS price, SUM(price) AS
> download_revenue, COUNT(1) AS downloads FROM songs_downloaded WHERE
> advertiser_id = 6553406 GROUP BY advertisement_id) AS sd ON a.id =
> sd.advertisement_id
> WHERE advertiser_id = 6553406
--
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