Re: "UNION ALL" is failing

The whole point of "with" is to factor out redundancy, and yet here you are 
going and repeating the 2 "with" declarations; also the declarations have the 
same names, which would be a problem, besides being redundant.

Try it like this instead:

with ...
(select ...)
union all
(select ...)
order by node

But moreover, I think you can avoid the union and doubled main selects, by 
saying this instead:

  with a as
  (
  select channel,node,accesses from storage where monthly = '11-06'
  ),
  b as
  (
  select channel,node,accesses from storage where monthly = '11-07'
  )
  select
  b.node
  from a right join b on a.node=b.node
  where a.accesses is null and b.channel in ('611 IVR', 'olam')
  order by node

-- Darren Duncan

Joy Smith wrote:
> with a as
> (
> select channel,node,accesses from storage where monthly = '11-06'
> ),
> b as
> (
> select channel,node,accesses from storage where monthly = '11-07'
> )
> 
> select
> b.node
> from a right join b on a.node=b.node
> where a.accesses is null and b.channel = ('611 IVR')
> order by node
> 
> 
> UNION ALL
> 
> 
> with a as
> (
> select channel,node,accesses from storage where monthly = '11-06'
> ),
> b as
> (
> select channel,node,accesses from storage where monthly = '11-07'
> )
> 
> 
> select
> b.node 
> from a right join b on a.node=b.node
> where a.accesses is null and b.channel = 'olam'
> order by node