Re: Search for lists
От | Daron Ryan |
---|---|
Тема | Re: Search for lists |
Дата | |
Msg-id | 4DFD844F.2030901@gmail.com обсуждение исходный текст |
Ответ на | Re: Search for lists (David Johnston <polobo@yahoo.com>) |
Список | pgsql-general |
Thanks. On 19/06/2011 8:09 AM, David Johnston wrote: > An alternative approach would be to select using a IN condition on the where clause and group by column 1 and column 2. Then, using this as a sub-select group by the resultant column 1 and a count on column two. The matching identifiersare those with a count equal to the number of entries in the original IN condition. > > Basically count how many of values each distinct key in column 1 matches and keep those keys where the count and the numberof values match. > > David J. > > > On Jun 18, 2011, at 17:51, Daron Ryan<daron.ryan@gmail.com> wrote: > >> Hello, >> >> I need to search a table to find sets of rows that have a column matching itself for the whole set and another columnmatching row for row with a list I am going to supply. The result I should receive should be value of the column thatmatches itself. >> >> For example given the following data in my table: >> >> 3; 1 >> 3; 2 >> 4; 8 >> 4; 9 >> 4; 10 >> >> I might need to search for 1,2. This should produce the result 3. Or if I were to search for 8, 9, 10 the result shouldbe 4. Searching for 8, 9 should produce an empty result as should 8, 9, 10, 11. >> >> Can anyone recommend a strategy? >> >> -- >> Sent via pgsql-general mailing list (pgsql-general@postgresql.org) >> To make changes to your subscription: >> http://www.postgresql.org/mailpref/pgsql-general
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